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Evaluate Sec(pi(2x+1)=2

  1. Sep 30, 2007 #1
    sec(pi)=2/2x+1
    -1=2/2x+1
    -2x-1=2
    -2x=3
    x=-3/2

    is this correct?
     
  2. jcsd
  3. Sep 30, 2007 #2
    is the original supposed to be sec(pi)(2x+1) = 2?
     
  4. Sep 30, 2007 #3
    sec(pi(2x+1)=2

    the original
     
  5. Sep 30, 2007 #4

    HallsofIvy

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    Staff Emeritus
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    That doesn't make any sense. You have two "(" and only one ")".
    The whole question is whether you mean sec(pi(2x+1))= 2 or sec(pi(2x)+ 1= 2 and you still haven't answered that.
     
  6. Sep 30, 2007 #5
    sec(pi(2x+1))= 2 is what i mean.
     
  7. Sep 30, 2007 #6

    dynamicsolo

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    Homework Helper

    So cos(pi(2x+1)) = ? Does that suggest an easier way to search for the values of x?
     
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