Evaluate the following limit without using L'Hospital's rule?

Benny · Mar 28, 2005

Can someone please show me, if possible, how to evaluate the following limit without using L'Hospital's rule?

[tex]
\mathop {\lim }\limits_{x \to \infty } \left( {1 - \frac{2}{{\log _e n}}} \right)^{\log _e n}
[/tex]

The answer is e^(-2).

Rewriting the terms in the bracket as a single term doesn't appear to get me anywhere. I tried taking the logarithm and exponentiating the limit but that still ended up requiring me to use L'Hospital's rule. Any help with evaluating the limit without using L'Hospital's rule would be good thanks.

maverick280857 · Mar 28, 2005

This is fairly straightforward...you need to know that

[tex]
\mathop {\lim }\limits_{n \to \infty } \left( {1 + \frac{1}{{n}}} \right)^{n} = e
[/tex]

Hope that helps...

Cheers
vivek

dextercioby · Mar 28, 2005

U misstyped it.

Assuming you're dealing with

[tex] \lim_{x\rightarrow +\infty}\left(1-\frac{2}{\ln x}\right)^{\ln x} [/tex]

,then i advise u to male the obvious substitution

[tex] \ln x= u [/tex]

and then use the definition of "e"...

Daniel.

Benny · Apr 7, 2005

It's a bit late, I haven't been online for a while, but thanks for the replies. There might be an error in my booklet but that's exactly(but without the base e, in the subject I'm taking it's assumed that the base is e) how the limit is written in my book.

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Evaluate the following limit without using L'Hospital's rule?

Benny

maverick280857

dextercioby

Benny

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