What is the Integral of sin^3(x)cos^2(x)?

  • Thread starter Jumpy Lee
  • Start date
  • Tags
    Integral
Just remember to always check your answer by differentiating it. In summary, the conversation was about solving the integral \int sin^3(x)cos^2(x)dx using the substitution method. The first attempt involved rewriting the integral in terms of sin and cos, but the person got stuck and asked for clarification. The other person then gave a hint to use the substitution u = cos x and guided the first person through the solution. The final answer was -cos^3x/3 + cos^5x/5 + c.
  • #1
Jumpy Lee
20
0

Homework Statement



[tex]\int sin^3(x)cos^2(x)dx[/tex]

The Attempt at a Solution



[tex]\int sin^3x(1-sin^2x)dx =[/tex] [tex]\int sin^3x- sin^5xdx[/tex]

i get stuck here what do i do next and is this even right
 
Physics news on Phys.org
  • #2
we could use complex numbers (de moivres theorem) here and express sin^5x, sin^3x in terms of sin5x, sin3x

(directly integratable)
 
  • #3
is that from calc 2?
 
  • #4
Jumpy Lee said:

Homework Statement



[tex]\int sin^3(x)cos^2(x)dx[/tex]

The Attempt at a Solution



[tex]\int sin^3x(1-sin^2x)dx =[/tex] [tex]\int sin^3x- sin^5xdx[/tex]

i get stuck here what do i do next and is this even right

HINT

[tex] \int \left(1-\cos^{2}x\right) \cos^{2}x \left(\sin x \ dx\right) [/tex]

Do you know how to use the substitution method ?
 
  • #5
yes i do know how to use substution
 
  • #6
Do you see a possible substitution in what i wrote ?
 
  • #7
u = cos x -du = sin x dx right?
 
Last edited:
  • #9
-[tex]\int (u^2 - u^4)du = [/tex] -u^3/3 + u^5/5 +c = -cos^3x/3 + cos^5x/5 + c
 
  • #10
Well done.
 

What is an integral?

An integral is a mathematical tool used to calculate the area under a curve. It is represented by the symbol ∫ and is used to find the total value of a function over a given interval.

How do you evaluate an integral?

To evaluate an integral, you must first determine the limits of integration, which are the starting and ending points for the interval. Then, you use integration techniques, such as substitution or integration by parts, to solve for the value of the integral.

What is the difference between a definite and indefinite integral?

A definite integral has specific limits of integration, while an indefinite integral does not. This means that a definite integral will result in a single numerical value, while an indefinite integral will result in a function with a constant of integration.

Why is evaluating integrals important in science?

Evaluating integrals is important in science because it allows us to calculate important values, such as area, volume, and probability, which are essential in many scientific fields. Integrals also help us understand the behavior of functions and solve problems in physics, chemistry, and engineering.

Are there any applications of integrals in real life?

Yes, there are many applications of integrals in real life, such as calculating the volume of a shape, finding the average value of a function, and determining the work done by a force. Integrals are also used in fields like economics, biology, and medicine to analyze data and make predictions.

Similar threads

  • Calculus and Beyond Homework Help
Replies
15
Views
783
  • Calculus and Beyond Homework Help
Replies
3
Views
341
  • Calculus and Beyond Homework Help
Replies
11
Views
692
  • Calculus and Beyond Homework Help
Replies
5
Views
680
  • Calculus and Beyond Homework Help
Replies
3
Views
788
  • Calculus and Beyond Homework Help
Replies
4
Views
127
  • Calculus and Beyond Homework Help
Replies
6
Views
546
  • Calculus and Beyond Homework Help
Replies
22
Views
1K
  • Calculus and Beyond Homework Help
Replies
2
Views
836
  • Calculus and Beyond Homework Help
Replies
1
Views
490
Back
Top