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Evaluate the integral ?

  1. Oct 1, 2009 #1
    Evaluate the integral... ?:(

    1. The problem statement, all variables and given/known data
    Suppose that the function f and g and their derivatives have the following values at x=0, x=1.

    [tex]f(0)=1, f(1)=3[/tex]
    [tex]f'(0)=5, f'(1)=\frac{1}{3}\right)[/tex]
    [tex]g(0)=1, g(1)=-4[/tex]
    [tex]g'(0)=\frac{1}{3}\right),g'(1)=-\frac{8}{3}\right)[/tex]

    Evaluate the integral:

    [tex]\frac{d}{dx}\right)(f^(^3^)(x^1^/^2))|[/tex] x=1

    2. Relevant equations



    3. The attempt at a solution
    f(1)=g(1)

    I know how to evaluate definite integrals and indefinate too, but i dont understand what it means by "evaluate the integral" in the question? I only see a derivative.

    To my understanding...

    [tex]\frac{d}{dx}\right)(f^(^3^)(x^1^/^2))|[/tex] x=1 .....
    [tex] = f^(^4^)(x^1^/^2)[/tex]

    So...
    [tex]\frac{d}{dx}\right)(f^(^3^)(x^1^/^2))=\frac{d^4y}{dx^4}\right)[/tex]

    And multiplying the differential dx and integrating the integrand [tex]f^(^4^)[/tex] will give you [tex]f^(^3^)(x^1^/^2)[/tex] so somehow I am suppose to integrate [tex]f^(^3^)(x^1^/^2)[/tex] until I get to f`(x) which should equal 5 or -1/3?

    I honestly don't understand the how to even start what the question is asking me. I just transferred to a different school and the professor already taught basic definite and indefinite integration in calculus I which I never learned in my calculus I class.

    ?:|
     
  2. jcsd
  3. Oct 1, 2009 #2

    LCKurtz

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    Re: Evaluate the integral... ?:(

    What does g have to do with it? Are you sure you have stated the problem correctly?
     
  4. Oct 1, 2009 #3
    Re: Evaluate the integral... ?:(

    Yes, I just read the question again and it's word for word. It's has a part A and B, but part b has no function g either. *shrug*
     
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