- #1

Sczisnad

- 9

- 0

## Homework Statement

integral ln(2x+1)dx

## Homework Equations

N/A

## The Attempt at a Solution

I tried integration by parts,

Let u = ln(2x+1), dv = dx, du = 2/(2x+1)dx, v = x

ln(2x+1)dx = ln(2x+1)*x-(integral)x*(2/(2x+1))dx

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- Thread starter Sczisnad
- Start date

- #1

Sczisnad

- 9

- 0

integral ln(2x+1)dx

N/A

I tried integration by parts,

Let u = ln(2x+1), dv = dx, du = 2/(2x+1)dx, v = x

ln(2x+1)dx = ln(2x+1)*x-(integral)x*(2/(2x+1))dx

- #2

foxjwill

- 354

- 0

Try u-substitution with [itex]u=2x+1[/itex].

- #3

Mark44

Mentor

- 36,342

- 8,297

So far, so good. The last integral can be turned into a simpler one by dividing 2x by 2x + 1, using polynomial long division. If you don't know that technique, it works out to 1 + -1/(2x + 1) in this problem.## Homework Statement

integral ln(2x+1)dx

## Homework Equations

N/A

## The Attempt at a Solution

I tried integration by parts,

Let u = ln(2x+1), dv = dx, du = 2/(2x+1)dx, v = x

ln(2x+1)dx = ln(2x+1)*x-(integral)x*(2/(2x+1))dx

- #4

mathstew

- 12

- 0

Try u subsitution (the obvious one...)

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