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Evaluating an Improper integral with square roots in the denominator and numerator

  1. Feb 16, 2010 #1
    http://www.freeimagehosting.net/image.php?9722bd5444.png

    Link: http://www.freeimagehosting.net/image.php?9722bd5444.png"

    I've tried to used integration by parts and u substitution and I've also tried just multiplying the fraction by the denominator (6-x)^(1/2) but I am still confused at how to approach this.
     
    Last edited by a moderator: Apr 24, 2017
  2. jcsd
  3. Feb 17, 2010 #2
    Re: Evaluating an Improper integral with square roots in the denominator and numerato

    Multiply and divide by [tex]\sqrt{6+x}[/tex].
     
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