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Can someone please help me in evaluating the following integral?

Im really bad with trig functions, and have been trying to work this out for ages.

[tex]\int \frac{sin x}{cos^2 x} dx[/tex]

Is there a way I can evaluate for [tex]\cos^2 x[/tex] ??????

Or is there something Im missing altogether?

Also,

Can someone please tell me how:

[tex]\int \frac{sec\theta}{cos\theta} dx =\ tan\theta + C[/tex]

????????????????

Im really bad with trig functions, and have been trying to work this out for ages.

[tex]\int \frac{sin x}{cos^2 x} dx[/tex]

Is there a way I can evaluate for [tex]\cos^2 x[/tex] ??????

Or is there something Im missing altogether?

Also,

Can someone please tell me how:

[tex]\int \frac{sec\theta}{cos\theta} dx =\ tan\theta + C[/tex]

????????????????

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