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## Main Question or Discussion Point

Can someone please help me in evaluating the following integral?

Im really bad with trig functions, and have been trying to work this out for ages.

[tex]\int \frac{sin x}{cos^2 x} dx[/tex]

Is there a way I can evaluate for [tex]\cos^2 x[/tex] ??????

Or is there something Im missing altogether?

Also,

Can someone please tell me how:

[tex]\int \frac{sec\theta}{cos\theta} dx =\ tan\theta + C[/tex]

????????????????

Im really bad with trig functions, and have been trying to work this out for ages.

[tex]\int \frac{sin x}{cos^2 x} dx[/tex]

Is there a way I can evaluate for [tex]\cos^2 x[/tex] ??????

Or is there something Im missing altogether?

Also,

Can someone please tell me how:

[tex]\int \frac{sec\theta}{cos\theta} dx =\ tan\theta + C[/tex]

????????????????

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