# Homework Help: Evaluationg triple integral

1. Mar 8, 2009

### -EquinoX-

1. The problem statement, all variables and given/known data

http://img19.imageshack.us/img19/2559/triple.th.jpg [Broken]

2. Relevant equations

3. The attempt at a solution

I get 16pi/3 (sqrt(2) -1) as the final result, but when I input the answer to the computer, it doesn't accept it. Am I doing a wrong integration/calculation anywhere? I double checked and I can't to find anything wrong.

Last edited by a moderator: May 4, 2017
2. Mar 8, 2009

### gabbagabbahey

It seems that when you multiplied by 2pi, you said 16/3* 2pi=16pi/3....that's not really true is it?

3. Mar 8, 2009

### -EquinoX-

oh so it should be 32pi/3 then.. thanks for pointing out the silly mistake

4. Mar 8, 2009

### foxjwill

You went from
$$-\frac{1}{3}\left(4^{3}{2}-8^{3}{2})-\frac{8}{3}$$
to
$$\frac{16}{3}(\sqrt{2}-1)$$
$$\frac{8}{3}(2\sqrt{2}-1)$$