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Homework Help: Evaluationg triple integral

  1. Mar 8, 2009 #1
    1. The problem statement, all variables and given/known data

    http://img19.imageshack.us/img19/2559/triple.th.jpg [Broken]

    2. Relevant equations



    3. The attempt at a solution

    I get 16pi/3 (sqrt(2) -1) as the final result, but when I input the answer to the computer, it doesn't accept it. Am I doing a wrong integration/calculation anywhere? I double checked and I can't to find anything wrong.
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Mar 8, 2009 #2

    gabbagabbahey

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    It seems that when you multiplied by 2pi, you said 16/3* 2pi=16pi/3....that's not really true is it?:wink:
     
  4. Mar 8, 2009 #3
    oh so it should be 32pi/3 then.. thanks for pointing out the silly mistake
     
  5. Mar 8, 2009 #4
    You went from
    [tex]-\frac{1}{3}\left(4^{3}{2}-8^{3}{2})-\frac{8}{3}[/tex]
    to
    [tex]\frac{16}{3}(\sqrt{2}-1)[/tex]
    instead of
    [tex]\frac{8}{3}(2\sqrt{2}-1)[/tex]
     
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