Evaluationg triple integral

1. The problem statement, all variables and given/known data

http://img19.imageshack.us/img19/2559/triple.th.jpg [Broken]

2. Relevant equations



3. The attempt at a solution

I get 16pi/3 (sqrt(2) -1) as the final result, but when I input the answer to the computer, it doesn't accept it. Am I doing a wrong integration/calculation anywhere? I double checked and I can't to find anything wrong.
 
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gabbagabbahey

Homework Helper
Gold Member
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It seems that when you multiplied by 2pi, you said 16/3* 2pi=16pi/3....that's not really true is it?:wink:
 
oh so it should be 32pi/3 then.. thanks for pointing out the silly mistake
 
You went from
[tex]-\frac{1}{3}\left(4^{3}{2}-8^{3}{2})-\frac{8}{3}[/tex]
to
[tex]\frac{16}{3}(\sqrt{2}-1)[/tex]
instead of
[tex]\frac{8}{3}(2\sqrt{2}-1)[/tex]
 

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