Evaporation of the tube-side coefficient in a heat exchanger

In summary, the conversation revolves around designing a reactor with internal cooling using water as the coolant. The problem is that the cooling water will be evaporated within the reactor, resulting in an increase in volume. The question is whether including a single expansion joint in the tubes within the reactor will be safe or cause other problems. The parameters of the cooling system are a 260°C isothermal reactor temperature with 110MW of cooling water required. It is suggested to pressurize the system and use an accumulator to account for changes in volume. Another option is to use liquid metal for cooling, but the decision to use water has already been made. The conversation also discusses the need to control the temperature of the steam and the importance of sizing the
  • #1
Hoplite
51
0
I've got a problem. I'm trying to design a reactor with internal cooling provided by water flowing through tubes directly within the reactor. Basically, it's like a shell and tube heat exchanger with an internal heat source.

The problem is that the cooling water is to be evaporated within the reactor, and I don't know how to account for the resulting increase in volume. If I pump the coolant in at a standard liquid speed of 2m/s, then the exist vapour will be at several kilometers per second. This is no doubt well above the speed of sound in steam and would obviously damage the pipes.

So, is it safe to just include a single expansion joint in the tubes within the reactor so that the inlet and outlet speeds are within safe range, or would that just cause other problems?

I can't find anything in the literature about evaporation of coolant streams, but I'm sure it's done in industry.
 
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  • #2
If I pump the coolant in at a standard liquid speed of 2m/s, then the exist vapour will be at several kilometers per second.
How did you figure that? I think the flow resistance would prevent that. One cannot do a simple mass balance and change in specific volume.

What are the parameters of the cooling system.

One may need to pressurize it, in which case, it is normal to have an accumulator on such a system to account for changes in volume.

Depending on the temperature, cooling with liquid metal (NaK) might be better, but that has it's own complications.
 
  • #3
I just realized I used the word "coefficient" in the title instead of coolant for some reason.

Astronuc said:
How did you figure that? I think the flow resistance would prevent that. One cannot do a simple mass balance and change in specific volume.
Well, if the mass of water entering the tubes is equal to the mass exiting, then the flow speed should be inversely proportional to the density. Of course, it not so possible to pump steam at that speed, but that’s my point.
Astronuc said:
What are the parameters of the cooling system.
260C isothermal reactor temperature with 110MW of cooling water required.
Astronuc said:
One may need to pressurize it, in which case, it is normal to have an accumulator on such a system to account for changes in volume.
Do you mean to pressurise it in order to prevent evaporation, to reduce the exit steam’s volume? I guess that might be the only option. Thanks.
Astronuc said:
Depending on the temperature, cooling with liquid metal (NaK) might be better, but that has it's own complications.
The decision to use water has already been made though. The steam has already been earmarked for use elsewhere within the process.
 
  • #4
Hi Hoplite,
Well, if the mass of water entering the tubes is equal to the mass exiting, then the flow speed should be inversely proportional to the density.
Yes, that's exactly the reason higher pressure is desirable as Astronuc suggests. If your reactor is at 260 C, consider a temperature just below that which can give you a decent dT between the reactor and water. Let's use 20 C just for starters. The final temperature depends considerably on heat transfer from the tubes to reactor gas. You want the reactor gas to tube heat transfer coefficient to be high enough to perform the cooling required.

Given a water saturation temperature of 240 C (260 C - 20 C) the saturation pressure for water is about 485 psia. Thus the saturated vapor density is about 1.045 lbm/ft3. You can control to this temperature by putting a thermocouple on the discharge and varying flow either using a control valve or VFD on your pump.

We do something similar for cryogenic systems in which a vaporizer is used to warm a stream of cryogenic liquid to ambient temperature. In this case, the discharge piping of the vaporizer is sized to handle the pumped flow assuming warm gas on the outlet of the vaporizer. I think you'd want to do the same thing, size the steam pipe to handle the vapor required. I'd think your company, assuming you work in industry, already has these sorts of tools available to do these calculations efficiently. Do you work in industry, or is this just a hypothetical question for a school project?
 
  • #5
I was wondering about the points made by Q_Goest.

This might be of use -

http://www.thermexcel.com/english/tables/eaubou1.htm
http://www.thermexcel.com/english/tables/vapeau1.htm


If this is a school or hypothetical project, that is one thing, but if this is an actual industrial design project, then must observe the applicable standards for design of Boiler and Pressure Vessels (e.g. ASME BPV Code).

Are the requirements for the steam supply 110 MW of steam at 260°C? Then one must also know the superheat or is it at saturation.
 
  • #6
Thanks for your help, guys.

It's actually the final design project for my degree, so it has to be designed in detail, but without the information we'd have available in industry.
 

What is the "evaporation of the tube-side coefficient" in a heat exchanger?

The evaporation of the tube-side coefficient refers to the rate at which liquid is converted into vapor on the inner surface of the heat exchanger tubes. This process is a crucial factor in the overall heat transfer efficiency of the heat exchanger.

Why is the evaporation of the tube-side coefficient important in a heat exchanger?

The evaporation of the tube-side coefficient directly affects the amount of heat that can be transferred between the two fluids in a heat exchanger. A higher coefficient means more efficient heat transfer and better performance of the heat exchanger.

How is the evaporation of the tube-side coefficient calculated?

The evaporation of the tube-side coefficient can be calculated using various equations that take into account factors such as the properties of the fluids, the geometry of the heat exchanger, and the flow conditions.

What factors can affect the evaporation of the tube-side coefficient in a heat exchanger?

The evaporation of the tube-side coefficient can be influenced by factors such as the type of fluid, its flow rate, the heat exchanger design, and the presence of any fouling or deposits on the inner surface of the tubes.

How can the evaporation of the tube-side coefficient be improved in a heat exchanger?

To improve the evaporation of the tube-side coefficient, various measures can be taken such as optimizing the flow conditions, using efficient heat exchanger designs, and ensuring regular cleaning and maintenance to prevent fouling on the inner surface of the tubes.

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