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Evaporation of water

  1. Apr 23, 2014 #1
    1. The problem statement, all variables and given/known data

    Water's heat of vaporization is 2260 kJ/kg. How much power would you need to apply to water so that the evaporation rate was .25 g/s?

    2. Relevant equations

    Not sure

    3. The attempt at a solution

    What equation can be used to find the given rate?
     
  2. jcsd
  3. Apr 23, 2014 #2

    adjacent

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    Gold Member

    You can use ##E=mL_v## and ##P= \frac{E}{t}##

    Please show your progress :smile:
     
  4. Apr 23, 2014 #3
    E=(.00025)(2260) -> E=.565 -> .565/1=.565. Hows that look to you?
     
  5. Apr 23, 2014 #4

    adjacent

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    Gold Member

    It looks correct. :smile:
    EDIT:Wait, the latent heat of vaporisation should be in SI units.Change the kJ to joules.
     
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