Evaporative cooling in a vacuum

  • Thread starter kawikdx225
  • Start date
  • #1
kawikdx225
83
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I am having a problem at work and I'm hoping some of the brains on this board can help.

I'm using a Focused Ion beam to induce insulator deposition using a siloxane liquid. The liquid is stored in a small container with a valve to let the gas escape the container. This small container is located inside a vacuum chamber.

The vacuum chamber has a pressure of 1.5e-6 millibar when the siloxane valve is closed.

When the valve is opened I see the pressure rise to 8.0e-6 which is where I want to perform deposition.

As I watch the pressure I notice a slow linear drop with time. This effect causes the deposition process to fail.

As far as I know the chamber pressure is determined by the vapor pressure of the liquid and the size of the valve(which also has a limiting aperture in it)

My questions are:
1. Is this pressure drop due to the temperature of the liquid dropping due to evaporative cooling? This drop in temperature would also drop the vapor pressure right?

2. Is there a formula to calculate the vapor pressure vs temperature, or to calculate how fast the liquid will cool in the presence of a vacuum? or some other formula to help me characterize this effect.

3. Could the gauge used to measure the pressure level become inaccurate in the presence of an insulator like siloxane? It's a hot cathode Ionization gauge.

4. Is there something else that could be going on that I haven't mentioned.

Thanks for any help
 

Answers and Replies

  • #2
S = k log w
66
0
Would Boyle's law's be of any help?
 
  • #3
kawikdx225
83
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I don't know, where do I find information on this law?

Thanks
 
  • #4
S = k log w
66
0
I had found several citations when I ran a google search.
 

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