# Even and odd sequence

1. Oct 5, 2009

### caramello

Hi, I'm sorry if I post this thread at the wrong section. I have a question regarding sequences.

Qn: if there is a sequence x(n) = (0.5)^n u(n), find the energies of the latter sequence of x(2n) and x(0.5n). Also, how the even and odd sequence of x(2n) and x(0.5n) relate to those of x(n)

first, i'm not sure what does it mean by "find the energies of the latter sequence of..." and second, i don't know how to relate those sequences to those of x(n). Is there anyone who can help me? Any help will be greatly appreciated.

Thanks!

2. Oct 5, 2009

### jbunniii

I'm not sure what is meant by "find the energies of the latter sequence" either.

How about starting with the sequence $x(n) = 0.5^n u(n)$? Can you write down an expression for the energy of this sequence? Can you evaluate the expression? Show us how far you are able to get.

3. Oct 5, 2009

### caramello

hmm.. actually i'm totally clueless on how to derive the energy of the sequence. I mean what does it actually mean when they want the energy?

is there some kind of formula to it? this is because we just start a new quarter here, and the professor went on really fast. I tried to look at the textbook but there's no formula for that either. I'm so confused.

Thank you.

4. Oct 5, 2009

### jbunniii

I assume this is for some sort of engineering course? If so, I believe the energy of a sequence $x(n)$ is typically defined as

$$E = \sum_{n=-\infty}^\infty |x(n)|^2$$

Does that look familiar?

5. Oct 5, 2009

### caramello

oh ya.. I think I've seen that somewhere, but I can't remember. Thanks for the recall.
So back to the question of the energy of x(n) = 0.5n u(n)
It means that it will be the sum from negative infinity to infinity of (1/4)^n

is that right?

6. Oct 5, 2009

### caramello

oh I think I've figured the answer out already. Thanks!

so that's when x(n) = (1/2)nu(n). but what if the question is more complicated, something like x(n) = (1/2)(n-1) u(n-2) + (1/3)n u(n-1)? how do we compute the energy of the sequence then?

Thank you!