- #1

issacnewton

- 980

- 22

Hello

I have some doubts about this problem which I have attached.

If we assume that both the clocks are started at the time the

airliner goes for a trip, then for an observer on the airliner,

when the airliner comes back to the New York, the time interval

would be a proper time interval since both the time measurements

are done at the same place on the airliner. But the

observer in New York is also not moving. So when the airliner

comes back and the observer in the ground stops his clock, his

measurement could also be considered proper time interval

since the measurement is again done at the same place.

Am I missing something ?

Thanks

[tex]\smile\smile\smile\smile[/tex]

I have some doubts about this problem which I have attached.

If we assume that both the clocks are started at the time the

airliner goes for a trip, then for an observer on the airliner,

when the airliner comes back to the New York, the time interval

would be a proper time interval since both the time measurements

are done at the same place on the airliner. But the

observer in New York is also not moving. So when the airliner

comes back and the observer in the ground stops his clock, his

measurement could also be considered proper time interval

since the measurement is again done at the same place.

Am I missing something ?

Thanks

[tex]\smile\smile\smile\smile[/tex]

#### Attachments

Last edited: