Hello, My question comes in two parts, I don't know if the first part is relevent to the second so i'll put it in anyway. a. Express 1 + root(3)i in polar form I can solve this to get: 2cis(pi/3) My problem is with part b. b. Solve the quadratic equation z^2 + 2z - root(3)i = 0, expressing your answers in exact cartesian form I used the quadratic formula (I don't like completing the square) to get: z = (-2 + root(4 + 4root(3)i))/2 and z = (-2 -root(4 + 4root(3)i))/2 However, i'm lost with the 'exact cartesian form' part. Any help would be appreciated, thanks.