Determine whether exact. If yes, solve.
(4t3y-15t2-y)dt + (t4+3y2-t)dy = 0
The Attempt at a Solution
So, yes it is exact.
fy= M = (4t3y-15t2-y)
f(t,y) = ∫ N dy
ft= 6t2y2-30ty+ g'(t)
This is where I've gotten stuck. I know I need to set this equal to M, and then all of the t's should cancel, but from what I've done, that won't work. So, this means I've made a mistake somewhere else.