Lcos(y)y' + sin(y) = 0
The Attempt at a Solution
I seperated them into their respective M and N functions. took their integrals:
[tex]\int Lcos(y)dy = Lsin(y) + g(y) + C[/tex]
[tex]\int sin(y)dx = -cos(y) + f(y) + C[/tex]
there the solution would be Lsine(y) -cos(y) + C.
this is confusing me a bit as I am used to seeing commonality between the two equations and the added f(y) and g(x) take form of the differences to create 2 similar equations... am i doing this right or am i missing something?