Last Question I Promise!(adsbygoogle = window.adsbygoogle || []).push({});

It says given the function (sq root x^2-x)/x-x^2 find the intervals in which it is defined and examine the particular limit. lim x-> 1+ (sq root x^2-x)/x-x^2 Well I found the intervals to be, -infinity<x<0 and 1<x<infinity. So to examine the limit tried plugging in 1+, but you get 0, so then I thought ok rearrange the function.

I tried multiplying by the conjugate and got confused, im not sure thats the right method since you just end up with (x^2-x)/(x-x^2)(sq root x^2-x).. then you can make the numerator -(x^2-x) and cancel it out with the denominator and your left with 1/(sqroot x^2-x) which is still 1/0... Any suggestions whut I am doing wrong? Thanks Again!

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Examine the limit

**Physics Forums | Science Articles, Homework Help, Discussion**