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## Main Question or Discussion Point

is This example correct?????

I made it up

Twin Z get close to a black hole to observe it (theoretically he is Not in orbit, Not moving but close in off to an black hole to be affect by the gravity of it, and the black is not moving in space or rotating)

And Twin X stay behind on the mothership which is not moving or affected by the a gravity field

We want to know the time dilation between the two twins due to gravity of the black hole

-M is the mass of the black hole. M = 21x10^30 kg

-G is the gravitational constant G = 6.67408 × 10^-11

-c is the speed of light c = 299 792 458 m/s

-rs is the Schwarzschild radius

rs = 2GM/c^2 = (2G*21*〖10〗^30)/〖299792458〗^2 = 31188.8450 meters

-r is the (theoretical) distance of twin Z from the center of the black hole r = 35 000 m

-T0 is the elapsed time for twin Z T0 = 10 days = 864 000 s

-T is the elapsed for twin X

Time dilation formula for no-moving and no-rotating object

T= T0/√(1-rs/r) =

(864 000)/√(1-(31 188.8450)/(35 000)) = 2 618 300.31930 seconds ≈ 30 days

When Twins Z comes back on the mother ship Twin X is 30-10= 20 days older

I made it up

Twin Z get close to a black hole to observe it (theoretically he is Not in orbit, Not moving but close in off to an black hole to be affect by the gravity of it, and the black is not moving in space or rotating)

And Twin X stay behind on the mothership which is not moving or affected by the a gravity field

We want to know the time dilation between the two twins due to gravity of the black hole

-M is the mass of the black hole. M = 21x10^30 kg

-G is the gravitational constant G = 6.67408 × 10^-11

-c is the speed of light c = 299 792 458 m/s

-rs is the Schwarzschild radius

rs = 2GM/c^2 = (2G*21*〖10〗^30)/〖299792458〗^2 = 31188.8450 meters

-r is the (theoretical) distance of twin Z from the center of the black hole r = 35 000 m

-T0 is the elapsed time for twin Z T0 = 10 days = 864 000 s

-T is the elapsed for twin X

Time dilation formula for no-moving and no-rotating object

T= T0/√(1-rs/r) =

(864 000)/√(1-(31 188.8450)/(35 000)) = 2 618 300.31930 seconds ≈ 30 days

When Twins Z comes back on the mother ship Twin X is 30-10= 20 days older

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