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Excited state hydrogen

  1. May 7, 2012 #1
    help please, for question: a hydrogen atom, initially in ground state, absorbs a photon, and is excited to its second excited state. What were the wavelength and the energy of the photon by the atom. Did i do it right.

    1/λ = (1.097*10^7)(1/n1^2 - 1/n2^2)

    1/λ = (1.097*10^7)(1/1^2 - 1/4^2)

    λ = 9.72*10^-8 m


    Energy = hc/λ

    = (6.626*10^-34*3*10^8)/(9.72*10^-8)

    = 2.045*10^-18 J
     
  2. jcsd
  3. May 7, 2012 #2

    jtbell

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    Staff: Mentor

    You appear to be using 4 as the value of n for the second excited state. Why is that?
     
  4. May 7, 2012 #3
    oh it should be 2 right ?
     
  5. May 7, 2012 #4

    jtbell

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    Staff: Mentor

    n = 1 is the ground state, which is not an excited state. So the first excited state would be...
     
  6. May 7, 2012 #5
    so would it be 2
     
  7. May 7, 2012 #6
    i think my n=1 would be 1 its grund state, excited state 2, would be n=3 ?
     
  8. May 7, 2012 #7

    jtbell

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    Staff: Mentor

    That's how I see it. :smile:
     
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