Executing Circuit: Troubleshooting R_c Short-Circuiting

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In summary: The current through the wire and batteries is infinite and the batteries would probably catch on fire.
  • #1
Rectifier
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Hey there!
I don't understand why you can't execute following circuits:

ir88wuy.jpg


It looks like ##R_c ## is short-circuited in ## a ##. But I can't see what the problem is in ##b##.

Can someone please help me?
 
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  • #2
Passive components are never a problem, do with them as you will. Pay attention to sources though.
 
  • #3
I have been sitting with this problem an hour now and I am pretty sure that it is something obvious, but I can't really see what the problem is with the sources :(
 
  • #4
Rectifier said:
Hey there!
I don't understand why you can't execute following circuits:

ir88wuy.jpg


It looks like ##R_c ## is short-circuited in ## a ##. But I can't see what the problem is in ##b##.

Can someone please help me?
There is more wrong with circuit (a) than the fact that RC is short circuited.

Do you know Kirchhoff's Voltage Law ?
 
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  • #5
SammyS said:
Do you know Kirchhoff's Voltage Law ?

Yep, the sum of voltages around a loop is 0.

##a##
Starting from 1V source - voltage across ##R_A## is 1 V according to KVL.

Starting from 2V source - voltage across ##R_B## is 2 V according to KVL.

Wich means that the inner loop containing ##R_A## and ##R_B## is not satisfied because equation (according to KVL) in that loop is ##1+(-2)=0## which is not true.

##b##
The same thing applies to ##b## as to ##a##.

Am I right?
 
  • #6
Rectifier said:
Yep, the sum of voltages around a loop is 0.

##a##
Starting from 1V source - voltage across ##R_A## is 1 V according to KVL.

Starting from 2V source - voltage across ##R_B## is 2 V according to KVL.

Wich means that the inner loop containing ##R_A## and ##R_B## is not satisfied because equation (according to KVL) in that loop is ##1+(-2)=0## which is not true.

##b##
The same thing applies to ##b## as to ##a##.

Am I right?
Yes.

You will find a number of such inconsistencies in these circuits.

In particular, can you find any loop(s) with only voltage sources and without any resistors?
 
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  • #7
SammyS said:
In particular, can you find any loop(s) with only voltage sources and without any resistors?

Sorry, but I don't think I understand your question. Should I remove the resistors from a and b in the problem? :)

If yes, then the hole circuit can be summarised in a circuit where the sources are put sieries but one battery has a reversed polarity.

- + + -
--l|---|l--

Thank you for your help!
 
  • #8
Rectifier said:
I can't see what the problem is in ##b##.
You can connect one terminal of a battery to one terminal of another battery. There are no problems there.

What you must never do is connect both terminals of a battery directly to those of another battery.
i0om5.gif


Why must you not do that? (Answer in at least 25 words please.)


I'm referring to ideal voltage sources
 
  • #9
NascentOxygen said:
What you must never do is connect both terminals of a battery directly to those of another battery.

Do you mean like that?
tMf3ZNf.jpg
 
  • #10
Rectifier said:
Do you mean like that?
tMf3ZNf.jpg
Actually, the polarities or opposite, but voltages are different so, yes, it's a big problem.
 
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  • #11
That's close to what I had in mind. Whether you connect + to + (and - to -), or + to - (and then - to +), it is still something you must never do. http://physicsforums.bernhardtmediall.netdna-cdn.com/images/icons/icon9.gif

Though were your sketch to have only one voltage source it would still be a forbidden arrangement (shorting out the voltage source).
 
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  • #12
When I connect sources like that:

tMf3ZNf.jpg


I get infinite current flowing through the wire and batteries. I think that the wire would have burned if I would have done that in real life.

I can't really picture the problem when it comes to the following setup since I don't know what happens when I connect the sources like that:

pzKrlYf.jpg


@SammyS
Yeah, that's what I stated in #7 by
- + + -
--l|---|l-- :)
 
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  • #13
Rectifier said:
When I connect sources like that:

[ IMG]http://i.imgur.com/tMf3ZNf.jpg[/PLAIN]

I get infinite current flowing through the wire and batteries. I think that the wire would have burned if I would have done that in real life.

I can't really picture the problem when it comes to the following setup since I don't know what happens when I connect the sources like that:

[ IMG]http://i.imgur.com/pzKrlYf.jpg[/PLAIN]

@SammyS
Yeah, that's what I stated in #7 by
- + + -
--l|---|l-- :)
In this case:

attachment.php?attachmentid=69164&stc=1&d=1398648967.jpg


If the voltage is exactly the same for both batteries/cells then the current is zero, so there's no problem.
 

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  • #14
SammyS said:
If the voltage is exactly the same for both batteries/cells then the current is zero, so there's no problem.

What happens when one V is bigger that the other?
 
  • #15
Rectifier said:
What happens when one V is bigger that the other?

Haven't you answered that already ?
 
  • #16
Oh, have I :O? I still don't get that case in paticular though.
 
  • #17
Rectifier said:
Oh, have I :O? I still don't get that case in paticular though.
It's a short circuit.

Using Kirchhoff gives an invalid equation.
 
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  • #18
SammyS said:
Using Kirchhoff gives an invalid equation.

Oh!
Thank you SammyS, NascentOxygen and gneill for helping me with this problem!
 
  • #19
Rectifier said:
What happens when one V is bigger that the other?
That arrangement has the EMFs opposing, so if one source is slightly different from the other, then the EMFs won't exactly cancel.

Let's say one EMF is 4.512 volts, and the other is 4.511 volts.
You can predict the loop current as (4.512 - 4.511) ÷ 0 =

We are considering ideal elements.
 
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  • #20
NascentOxygen said:
You can predict the loop current as (4.512 - 4.511) ÷ 0 =

We are considering ideal elements.

Shouldnt we take a batteries inner-resistance into consideration?
 
  • #21
Rectifier said:
Shouldnt we take a batteries inner-resistance into consideration?
I think these are considered to be ideal voltage sourses.

Otherwise, yes, internal resistance should be considered.
 
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1. What is a short-circuit in a circuit?

A short-circuit is an electrical malfunction in a circuit where the current flows through a path with low resistance instead of the intended path, causing the circuit to fail. This can result in overheating, damage to components, and even fire hazards.

2. How can I identify a short-circuit in my circuit?

To identify a short-circuit, you can use a multimeter to check for continuity between the power source and the ground. If there is continuity, it means there is a short-circuit present. You can also visually inspect the circuit for any charred or damaged components.

3. What are the common causes of short-circuiting in a circuit?

Short-circuits can be caused by various factors, such as loose connections, damaged or faulty components, incorrect wiring, or overheating due to excessive current flow. They can also occur due to physical damage to the circuit or exposure to moisture or other contaminants.

4. How can I troubleshoot a short-circuit in my circuit?

To troubleshoot a short-circuit, you can start by visually inspecting the circuit for any obvious damage. Next, you can use a multimeter to check for continuity and isolate the location of the short-circuit. Once identified, you can carefully replace or repair the damaged components to fix the issue.

5. How can I prevent short-circuiting in my circuit?

To prevent short-circuiting, it is important to follow proper safety measures while working with circuits, such as turning off the power source before making any changes, using appropriate insulation materials, and avoiding overloading the circuit with excessive current. Regular maintenance and inspection of the circuit can also help identify and fix any potential issues before they lead to a short-circuit.

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