(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two forces, F1 and F2, act on the 7.00-kg block shown in the drawing. The magnitudes of the forces are F1=65.9 N and F2=22.7 N. Take the positive direction to be to the right. Find the horizontal acceleration of the block, including sign.

http://img522.imageshack.us/my.php?image=forcett9.jpg

2. Relevant equations

[tex]\Sigma[/tex]F = ma or a = [tex]\Sigma[/tex]F / m

[tex]\Sigma[/tex]F - Net Force (F1 + F2 = Net F)

m - mass

a - acceleration

3. The attempt at a solution

F1 = 65.9N

F1 * Sin = 61.9N

F1 * Cos = 22.6N

F2 = 22.7 N

F2 Opposite Force = -22.7 N

(-) 22.7 N + (+) 22.54 N = 7 kg*a

(-).16 N = 7 kg*a

(-).16 N / 7 kg = a

(-)0.023 m/s[tex]^{2}[/tex]

I'm not quite sure what I'm doing wrong as when I try to use this answer it is marked as incorrect so any help would be most appreciated.

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# Homework Help: Exercise in Net Force

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