- #1
KachinaEarth
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Homework Statement
Two forces, F1 and F2, act on the 7.00-kg block shown in the drawing. The magnitudes of the forces are F1=65.9 N and F2=22.7 N. Take the positive direction to be to the right. Find the horizontal acceleration of the block, including sign.
http://img522.imageshack.us/my.php?image=forcett9.jpg
Homework Equations
[tex]\Sigma[/tex]F = ma or a = [tex]\Sigma[/tex]F / m
[tex]\Sigma[/tex]F - Net Force (F1 + F2 = Net F)
m - mass
a - acceleration
The Attempt at a Solution
F1 = 65.9N
F1 * Sin = 61.9N
F1 * Cos = 22.6N
F2 = 22.7 N
F2 Opposite Force = -22.7 N
(-) 22.7 N + (+) 22.54 N = 7 kg*a
(-).16 N = 7 kg*a
(-).16 N / 7 kg = a
(-)0.023 m/s[tex]^{2}[/tex]
I'm not quite sure what I'm doing wrong as when I try to use this answer it is marked as incorrect so any help would be most appreciated.