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## Homework Statement

How would one show 'nicely' that for any 2x2 non-zero matrix A, there exists some 2x2 non-zero matrix C such that AC=CA=0? I can see how to show it by showing that the determinant is '0' for both A and C, so when you multiply out component-wise for AC=0, CA=0, you get 8 equations for the components of A/C and I can show that they can all be paired up as 'equivalent' equations (using ad=bc for both matrices) so in fact you have 4 equations in 4 unknowns - the 4 components of c - so they are solvable, so there does exist some appropriate 'c' - however that's clearly a horrible and slow way of proving the result, can anyone suggest a faster or neater method?

Thanks a lot!