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Calculus and Beyond Homework Help
Expanding a function in terms of a vector
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[QUOTE="Fredrik, post: 5164070, member: 14944"] The domain of L is a subset of ##\mathbb R##, not a subset of ##\mathbb R^n## with n>1, so L doesn't have partial derivatives. Maybe that's just a terrible notation for ##L'(\pmb v^2)##. I would start like this and then just use the chain rule: $$L(\mathbf v^2+2\pmb v\cdot\pmb\varepsilon+\pmb\varepsilon^2) = L(\pmb v^2)+\varepsilon_i\frac{\partial}{\partial \varepsilon_i}\bigg|_{\pmb 0} L(\pmb v^2+2\pmb v\cdot\pmb\varepsilon+\pmb\varepsilon^2).$$ [/QUOTE]
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Calculus and Beyond Homework Help
Expanding a function in terms of a vector
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