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Any continuous function of period 2L can be expanded as a Fourier series

f(x)=a0/2+∑(from n=1 to∞) (ancos(n pi x/L)+bnsin(n pi x/L))

Using ∫(from -L to +L) sin(m pi x/L)sin(n pi x/L)dx=L kronecker delta m n

Show that

Bn=1/L∫(from -L to+L) sin(n pi x/L)f(x) dx

i am seriously stuck on this - kinda can't stand proof questions

thanks in advance