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## Homework Statement

Consider a Negative Binomial random variable Y ~ NB(r, p). Show (from first principles!) that E[Y] is r/p. Why does this imply Y is proper?

## Homework Equations

I have no idea how to use latex, so this may be messy:

pmf of Y: [ (k+r-1)! / k!(r-1)! ] * (1-p)^r * p^k

## The Attempt at a Solution

E[Y] = sigma(r=1 to k); r * (1-p)^r * p^k * [ (k+r-1)! / k!(r-1)! ]

I have no idea of how to manipulate the factorials...I know that sum of geometric random variables is a negative binomial rv. Since the expectation of a geometric random variable is 1 / p - sum them to r and we get r / p (expectation of NB). However I have to do this with first principles and I'm stumped.

I see a lot of possibilities.... p^k / k! is a known series..I even thought about this

for the r * (1-p)^r * p^k part:

= r * q^r * p^k

=r * q^(r-1) * q * p^k

= d/dq(q^r) * q * p^k

Hope this makes some sense....