"A bowl contains 10 chips, of which 8 are marked $2 each and 2 are marked $5 each. Let a person choose, at random and without replacement, 3 chips from this bowl. If a person is to recieve the sum of the resulting amounts, find his expectation."(adsbygoogle = window.adsbygoogle || []).push({});

Here is my attempt:

The possible values for X are 6(2,2,2), 9(2,2,5), and 12(2,5,5). So, now we have to calculate p(x) for each of these values in order to find the expectation.

p(6) = (8 C 3)/(10 C 3), where a C b is a choose b.

p(9) = (8 C 2)(2 C 1)/(10 C 3)

p(12) = (8 C 1)(2 C 2)/(10 C 3)

These don't add up to 1 however. and I'm sure that p(6) is not equal to p(9). Could someone explain to me what I'm doing wrong in calculating p(9) and p(12). I can do the rest of the problem from there. I just can't think of what I'm doing wrong for those two. Thanks.

**Physics Forums - The Fusion of Science and Community**

# Expectation problem

Have something to add?

- Similar discussions for: Expectation problem

Loading...

**Physics Forums - The Fusion of Science and Community**