I've tested the circuit above, when the switch is in the 2nd position (not the one on the picture) and got the below graph from the plotted data I received.
The capacitor C1 has been charged to 4V, and will start to discharge through R3.
I'll have to explain this graph in my report.
The blue graph is the discharging of C1, the green graph is the charging of C2 and lastly, the red graph is the voltage across R3.
Why is the green graph starting below 0 V? And why is the red line starting above 4V?
The x axis of the graph represent the time axis, and the y axis represent the voltage.
The Attempt at a Solution
I believe that the capacitor C2 (green graph) is below 0 because it hasn't been short circuited (discharged properly). But why is it affecting the graph with negative voltage, and not positive?
Also, the voltage across R3 (red graph) I believe is affected by the negative voltage of the capacitor C2.
When the capacitor C1 starts to discharge, C2 will have no voltage across it. All of the voltage in this circuit will be across R1. How can the capacitor C2 be "charged" (from not being properly discharged) with negative value?
How can I explain this properly?