# Homework Help: Exploding object (momentum problem)

1. Oct 24, 2004

### TraceBusta

Well I think conservation of momentum is needed here.

Jay and Dave decide that the best way to protest the opening of a new incinerator is to launch a stink bomb into the middle of the ceremony. They calculate that a 5.5 kg projectile launched with an initial speed of 36 m/s at an angle of 30° will do the trick. The bomb will explode on impact, no one will get hurt, but everyone will stink. Perfect. However, at the top of its flight, the bomb explodes into two fragments, each having a horizontal trajectory. To top it off--this really isn't their day--the 1.8 kg fragment lands right at the feet of Dave and Jay.

(a) How far from Dave and Jay does the 3.7 kg fragment land?
(b) Find the energy of the explosion by comparing the kinetic energy of the projectiles just before and just after the explosion.

I first solved the x-velocity of the object at the time of explosion (Vx=Vo cos theta) which i think is right. So using that, i solved for P. Then I solved the velocity of the small object and time it took to land at their feet. so i could solve for the velocity of the big object by using 5.5 kg*Vx=3.7 kg*v-(1.8 kg*V1.8) And then I just used that velocity and the same time the other object was in the air to find the distance. I got 99.728m for a but that is wrong. I don't know how to start (b) either.

2. Oct 24, 2004

### thermodynamicaldude

The time of explosion is when the vertical velocity = 0 (since it is at the top of the path). Use this info when calculating......

part B just involves finding the kinetic energy of the object before it explodes, which is:

KE= 1/2mv^2

THe KE afterwards would just be the same thing, except for both objects.

KE(total) = KE(object 1) + KE(object 2).

Note that the potential energy is not factored into the equation, because the objects before and after the explosion are still at the same height, and thus have the same potential energy, as Potential Energy = mgh.