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## Homework Statement

A projectile is launched with speed v

_{0}at an angle [tex]\theta[/tex] with respect to the horizontal. At the peak of its motion, it explodes into two pieces of equal mass, which continue to move in the original plane of motion. One piece strikes the ground a horizontal distance D farther from the launch point than the point directly below the explosion at a time t<v

_{0}sin[tex]\theta[/tex]/g. How high does the other piece go? Answer in terms of v

_{0}, [tex]\theta[/tex], g, and t.

## Homework Equations

m1v1=m2v2

h=v

_{0}

^{2}sin

^{2}([tex]\theta[/tex]/g

## The Attempt at a Solution

I know I should be doing a momentum balance in the vertical direction before and after the collision, but I'm struggling to get the right equation. Any help would be appreciated