- #1

huskydc

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i know both momentum and energy conservation applies here, but don't know where to start...

both carts are initially at rest,

so I'm guessing : PE(initial) = PE(final) + KE (final)

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- Thread starter huskydc
- Start date

- #1

huskydc

- 78

- 0

i know both momentum and energy conservation applies here, but don't know where to start...

both carts are initially at rest,

so I'm guessing : PE(initial) = PE(final) + KE (final)

- #2

Galileo

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- #3

huskydc

- 78

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also, wouldn't PE final be zero too? after the carts are released, the spring would be relaxed again, thus no compression, thus zero..

that'll make it: initial PE = final KE

but i don't know where to go from here

that'll make it: initial PE = final KE

but i don't know where to go from here

Last edited:

- #4

Galileo

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What are the expressions for the initial energy, initial momentum, final momentum and final energy?

- #5

huskydc

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it goes....

.5kx^2 = .5m(1)v(1)^2 + .5m(2)v(2)^2

does it make sense? but the problem now is i have two variables to solve...one equation...

- #6

Doc Al

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Don't forget conservation of momentum. That will give you the second equation that you need.

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