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## Homework Statement

Imagine another planet with an acceleration of 10.00 m/s^2 at its equator when ignoring the rotation of the planet. The radius is 6.2 x10^6 m. An object dropped at the equator yields an acceleration of 9.70 m/s^2. Determine the length of 1 day on this planet.

## Homework Equations

## The Attempt at a Solution

My teacher taught me how to solve this question, but there is just one step I don't understand

10.00m/s^2 - 9.70m/s^2 = 0.3m/s^2 (centripetal acceleration)

why does subtracting these two values give us the centripetal acceleration??

On a test, if I get a similar question I know I have to subtract the two values, but I really want to learn the reason behind it.