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Haorong Wu
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- Are there any restrictions of choosing circles in Clausius theorem?
Hi, I am currently reading Introduction to statistical physics by Huang. In the section of entropy, it reads
But what if I choose ##R-P## as a closed cycle? Then in a similar process, I should have ##\int_{R} \frac {dQ} {T} \leq \int_{P} \frac {dQ} {T}## and ##S \left ( B \right ) - S \left ( A \right ) \leq \int_{A}^{B} \frac {dQ} {T}##, which are contradicted to the equations above. I am not sure what goes wrong. Maybe there are some restrictions when I choose a closed cycle, but I did not find any relevant context in the book.
Let ##P## be an arbitrary path from ##A## to ##B##, reversible or not. Let ##R## be a reversible path with the same endpoints. Then the combined process ##P-R## is a closed cycle, and therefore by Clausius' theorem ##\int_{P-R} dQ/T \leq 0##, or
##\int_{P} \frac {dQ} {T} \leq \int_{R} \frac {dQ} {T}##.
Since the right side is the definition of the entropy difference between the final state ##B## and the initial state ##A##, we have ##S \left ( B \right ) - S \left ( A \right ) \geq \int_{A}^{B} \frac {dQ} {T}## where the equality holds if the process is reversible.
But what if I choose ##R-P## as a closed cycle? Then in a similar process, I should have ##\int_{R} \frac {dQ} {T} \leq \int_{P} \frac {dQ} {T}## and ##S \left ( B \right ) - S \left ( A \right ) \leq \int_{A}^{B} \frac {dQ} {T}##, which are contradicted to the equations above. I am not sure what goes wrong. Maybe there are some restrictions when I choose a closed cycle, but I did not find any relevant context in the book.
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