- #1
Vali
- 48
- 0
$$\lim_{n\rightarrow \infty }(2-2^{\frac{1}{n+1}})^{n}$$
I wrote that $L=e^{\lim_{n\rightarrow \infty }(n)(1-2^{\frac{1}{n+1}})}$
how to continue ?
I wrote that $L=e^{\lim_{n\rightarrow \infty }(n)(1-2^{\frac{1}{n+1}})}$
how to continue ?