- #1
siemieniuk
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Hey all... I got an answer to this, but I'm not sure if I did it correctly.
q: A body of mass 8.0kg is traveling at 2.0 m/s under the influence of no external agency. At a certain instant an internal explosion occurs, splitting the body into two chunks of 4.0 kg mass each; 16 joules of translational kinetic energy are imparted to the two chunk system by the explosion. Neither chunk leaves the line of the original motion. Determine the speed and direction of motion of each of the chunks after the explosion.
a: I assumed the original block was just 2 4kg blocks with the same kinetic energy traveling in the same direction. (to the right)
Then, I subtracted 16J from the 8J of kinetic energy that the left most piece had because that's the way the 16J would be directed from the explosion.
When I put that into the calculation, I got 2.0 m/s (to the left) for the left block, and when I put 24 J (to the right) into the kinetic energy equation, I got the right block traveling 3.46 m/s (to the right).
Did I do this correctly??
Steve
q: A body of mass 8.0kg is traveling at 2.0 m/s under the influence of no external agency. At a certain instant an internal explosion occurs, splitting the body into two chunks of 4.0 kg mass each; 16 joules of translational kinetic energy are imparted to the two chunk system by the explosion. Neither chunk leaves the line of the original motion. Determine the speed and direction of motion of each of the chunks after the explosion.
a: I assumed the original block was just 2 4kg blocks with the same kinetic energy traveling in the same direction. (to the right)
Then, I subtracted 16J from the 8J of kinetic energy that the left most piece had because that's the way the 16J would be directed from the explosion.
When I put that into the calculation, I got 2.0 m/s (to the left) for the left block, and when I put 24 J (to the right) into the kinetic energy equation, I got the right block traveling 3.46 m/s (to the right).
Did I do this correctly??
Steve
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