- #1

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Solve for x,

(73/10)^(x-1)+5 - 3^(x+1)=0

(73/10)^(x-1)+5 - 3^(x+1)=0

- Thread starter NZS92
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- #1

- 4

- 0

Solve for x,

(73/10)^(x-1)+5 - 3^(x+1)=0

(73/10)^(x-1)+5 - 3^(x+1)=0

- #2

jedishrfu

Mentor

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- #3

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my first work:

7.3^(x-1)+5=3^(x+1)

log_(3) (7.3^(x-1)+5)=x+1

e^(log_3 (7.3^(x-1)+5) / e^x = e

(7.3^(x-1)+5)/e^x =e

7.3^(x-1)+5= ee^x

7.3^(x-1) -ee^x=-5

my second work,

7.3^(x-1)=3^(x+1)-5

(x-1)log(73/10)=log(3^(x+1)-5)

xlog(73/10)-log(73/10) = log(3^(x+1)-5)

(e^(xlog(73/10)) / (e^(log73/10) = 3^(x+1)-5

e^(xlog73/10) = 3^(x+1) e^(log73/10)-5e^(log73/10)

- #4

Mentallic

Homework Helper

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[tex]\left(\frac{73}{10}\right)^{x-1}-3^{x+1}+5=0[/tex]

right? Because I don't believe this expression can be solved algebraically. You can, of course, find a numerical solution to the problem however.

- #5

jedishrfu

Mentor

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I agree with Mentallic, if its as he wrote there is no simple algebraic solution only a numeric one.

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