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Exponential Functions

  1. Apr 8, 2008 #1
    1. (3*square root of 2)^square root of 2 How do I simplify this and other exponential expressions?
    2. 3^(power of 2*x)-1=3^(power of x) + 2 How do i solve this?

    I don't know how to attempt it...Help please
     
  2. jcsd
  3. Apr 8, 2008 #2
    Regarding your first question: you can't, really. Subjectively, there's no "simpler" form than what you already have.

    Regarding your second question: define y=3^x, and recast your equation in terms of y. Can you solve this?
     
  4. Apr 8, 2008 #3
    according to glencoe algebra 2 number 1 can be simplified even more but they dont tell HOW????

    no [​IMG] thats what its supposed to look like, i have to find x
     
  5. Apr 8, 2008 #4

    symbolipoint

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    Try this: instead of 2^(1/2), use some variable, r, for the (1/2). Now you have
    something like (3*2^r)^(2^r), convert this into ordinary algebraic notation so it is easier to understand; and then use your laws of exponents.
     
  6. Apr 8, 2008 #5

    symbolipoint

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    Actually what I obtain is not much clearer. Example seems like a calculator exercise.
     
  7. Apr 8, 2008 #6

    symbolipoint

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    Now, I find this:

    (3^(1/2))*2^((2^(1/2))/2 )

    It would look better if I had access to TEX right now.
    Three to the square root of two power, multiplied by two to the [square root of two] over two power. It may read complicated, but it looks neat on my paper.
     
  8. Apr 9, 2008 #7
    You can always use latex in your posts by typing [tex] your latex code [ /tex]. (without the space in front of the /)
     
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