Exponential of ladder operator

  • Thread starter binbagsss
  • Start date
  • #1
1,232
10
Homework Statement:
below
Relevant Equations:
below
I'm just trying to follow the below
expop.png

And I understand all, I think, except what's happened to the term when A hits 1: [A,1] ?
If I'm correct basically we're just hitting on the first operator so reducing the power by one each time of the operator in the right hand bracket

thanks
 

Answers and Replies

  • #2
tnich
Homework Helper
1,048
336
If I understand this correctly, ##1## is the identity operator. So what would be the value of ##[A,1]##?
 
  • #3
165
38
[A,1]=0 since 1 is pure number!
 
  • #5
165
38
omg i think i need some sleeep ! thank you haha :)
A typo! 1 here refers to identity operator as @tnich says. Anyways,final result is same
 

Related Threads on Exponential of ladder operator

Replies
2
Views
2K
Replies
17
Views
1K
Replies
18
Views
1K
  • Last Post
Replies
4
Views
4K
  • Last Post
Replies
1
Views
525
Replies
1
Views
698
  • Last Post
Replies
7
Views
12K
Replies
7
Views
1K
  • Last Post
Replies
2
Views
1K
Replies
2
Views
2K
Top