- #1
naspek
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e ^ (-2 ln |x + 1|) = e ^ ln [1 / (x + 1)^2]
how can this happen?
can anyone explain to me the process of this equation..
how can this happen?
can anyone explain to me the process of this equation..
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Nice how you absolutely did not try to hide the fact that you copied this from another forum.
The answer to your question: it is a known calculation rule for logarithms that
y ^{a}log(x) = ^{a}log(x^{y})
for any number a.
I haven't see notation like that before. Is ^{a}log supposed to represent the log base a of something?
The notation that is used more often for this property of logarithms, I believe, is this:
log_{a} (x^{y}) = y log_{a}(x)