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Exponential theory

  • Thread starter naspek
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  • #1
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e ^ (-2 ln |x + 1|) = e ^ ln [1 / (x + 1)^2]

how can this happen?
can anyone explain to me the process of this equation..
 
Last edited:

Answers and Replies

  • #2
CompuChip
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Nice how you absolutely did not try to hide the fact that you copied this from another forum.

The answer to your question: it is a known calculation rule for logarithms that
y alog(x) = alog(xy)
for any number a.
 
  • #3
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Nice how you absolutely did not try to hide the fact that you copied this from another forum.

The answer to your question: it is a known calculation rule for logarithms that
y alog(x) = alog(xy)
for any number a.
I haven't see notation like that before. Is alog supposed to represent the log base a of something?

The notation that is used more often for this property of logarithms, I believe, is this:
loga (xy) = y loga(x)
 
  • #4
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Thanks Mark44 =)
 
  • #5
CompuChip
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Homework Helper
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I haven't see notation like that before. Is alog supposed to represent the log base a of something?

The notation that is used more often for this property of logarithms, I believe, is this:
loga (xy) = y loga(x)
Right, sorry.
Where I come from alog is standard notation.
But that is what I meant.
 
  • #6
33,173
4,858
I figured that's what it meant, but it's something I haven't run across it before.
 

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