Exponentiation Problem

Problem in english:
Whereas 2x = $\alpha$ and 2y = $\beta$, write the expression (0,125)y-2x in function of $\alpha$ and $\beta$

Without logarithm...

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Answers and Replies

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HallsofIvy
Science Advisor
Homework Helper
$0,125= 1/8= 2^{-3}$ so $(0,125)^{y- 2x}= (2^{-3})^{y-2x}= 2^{-3y+ 6x}$. Can you finish it?

Hehe i found that too but i can't put in function of alfa and beta =/

Answer in book is:
$\alpha$6
$\overline{\beta}$3

But i don't know how to do.

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Hehe i found that too but i can't put in function of alfa and beta =/

Answer in book is:
$\alpha$6
$\overline{\beta}$3

But i don't know how to do.
Did you know that $a^{b-c}=\frac{a^b}{a^c}$?

No i don't see it '-' thank you very much xD

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