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Exponentiation Problem

  • #1
Problem in english:
Whereas 2x = [itex]\alpha[/itex] and 2y = [itex]\beta[/itex], write the expression (0,125)y-2x in function of [itex]\alpha[/itex] and [itex]\beta[/itex]

Without logarithm...
 

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Answers and Replies

  • #2
HallsofIvy
Science Advisor
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[itex]0,125= 1/8= 2^{-3}[/itex] so [itex](0,125)^{y- 2x}= (2^{-3})^{y-2x}= 2^{-3y+ 6x}[/itex]. Can you finish it?
 
  • #3
Hehe i found that too but i can't put in function of alfa and beta =/

Answer in book is:
[itex]\alpha[/itex]6
[itex]\overline{\beta}[/itex]3

But i don't know how to do.
 
Last edited:
  • #4
724
0
Hehe i found that too but i can't put in function of alfa and beta =/

Answer in book is:
[itex]\alpha[/itex]6
[itex]\overline{\beta}[/itex]3

But i don't know how to do.
Did you know that [itex]a^{b-c}=\frac{a^b}{a^c}[/itex]?
 
  • #5
No i don't see it '-' thank you very much xD
 
Last edited:

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