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Exponents help - I Think?

  1. Dec 4, 2006 #1
    This is the formual
    Points = (PrizePool^1/2) / (PlaceFinished^3/5)

    Here are two examples:

    [tex]266.08=(70,800^{1/2})/(1^{3/5})[/tex]
    [tex]137.64=(70,800 ^{1/2})/(3^{3/5})[/tex]

    Now I got the first part because it's basically a the square root of the the number. But how do I do the 3/5 one?

    Thanks in advance.
     
    Last edited by a moderator: Dec 4, 2006
  2. jcsd
  3. Dec 4, 2006 #2
    take the fifth root of the number and then cube it.
     
  4. Dec 4, 2006 #3
    How do you do that honestly?
     
  5. Dec 4, 2006 #4
    what do you mean by how ?
     
  6. Dec 4, 2006 #5

    radou

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    I can't say I understand your problem, but, as courtrigrad said, [tex]a^{m/n}=\sqrt[n]{a^m}[/tex], I hope that comes in handy.
     
  7. Dec 4, 2006 #6
    how do you cube it?
     
  8. Dec 4, 2006 #7

    HallsofIvy

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    Do you know what "cube" MEANS? Just multiply it by itself twice: a3= a*a*a. It's much harder to find the fifth root! The simplest way to do a problem like that is to use a calulator that allows exponents: The TI calculators, for example, have a "^" key. [itex]3^{3/5}[/itex] is 3 "^" (3/5) on such a calculator.
    You can also do it using the "log" and "10x" keys:
    [tex]3^{3/5}= 10^{(3/5)log 3}[/itex]
     
  9. Dec 4, 2006 #8
    So is it possible by using a regular calculator?
     
  10. Dec 4, 2006 #9

    CRGreathouse

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    If you have a root key or a log key, yes.
     
  11. Dec 5, 2006 #10

    HallsofIvy

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    What do you mean by a "regular calculator"? AS CRGreathouse said, if your calculator as either a general "root" key, usually with a "xy" or "^" on it, or if it has a "log" (typically with 10x as "second function") then you can do such calculations, yes.
     
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