How do I express this in polar coordinates? (x-h)^2+(y-k)^2= h^2+k^2 It is a circle with k and h greater than 0.
go to: http://mathworld.wolfram.com/PolarCoordinates.html I think the transforms would be x--> rcos theta y--> r sin theta h --> R cos theta' k --> R sin theta' 4 prameters to describe the points on a shifted circle (shifted orgin because of the k and h terms) in either cartesian or polar coordinates Not sure, but I think.
In two dimensions, the transformations are: [tex]x = r\cos \theta, \qquad y = r\sin \theta[/tex] That's all you need.
Yeah this makes sense. Sorry for my mistake. You'll only need two variables to plot a 1-d object in a 2d space. You would need four parameters to specify a shifted circle in either coordinate system. (The k and h parameters will propagate through your transformation.) You could transform this shift into polar coordinates as well (and you would have to if this was a complicated mechanics problem) but you don't even need to bother with this because it is given as a constant. Hope I didn't mess you up. Sorry again.