- #1

thisisfudd

- 56

- 0

Do I just use P=IV?

But that leaves a lot of "extraneous" information.

My second thought was to find resistance:

R = p (L/A)

A = pir^2 = 1.29E-3^2 x pi = 5.23E-6

R = (1.68E-8) x (2.7/5.23E-6)

R = .00867

But then I'm not sure what to do from there.

Using P=IV I get 1800 W. But then do I have to multiply by length and area?