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Extracted energy of Uranium

  1. Dec 15, 2008 #1
    1. The problem statement, all variables and given/known data

    What proportion of the total energy in Uranium-235 is extracted through nuclear fission?

    In 2001, the world electricity consumption was 13.81 trillion kWh. Assuming 50% efficiency in converting and distributing the power, and imagining that all production was nuclear, how many kg of radioactive waste (Xe and Sr) would have been created?

    2. Relevant equations

    1 n + 235U -> 140Xe + 94Sr + 2 n + gamma

    1 MeV = 1.602x10^-13 J
    1 kWh = 3.6x10^6 J

    3. The attempt at a solution

    Using the reaction and the binding energies the released energy is equal to 175 MeV.

    how do i calculate the proportion of the extracted and total energy?

    how do i use the % of efficiency and the global production to calculate the waste?
    Please help.
     
  2. jcsd
  3. Dec 15, 2008 #2
    i forgot that the total energy of Uranium is the binding energy i think that is 1786 MeV.
     
  4. Dec 15, 2008 #3
    i dont know how to relate the total and the released energy, and how to relate the 50% efficiency with the released energy and the global consumption.... please help :(?
     
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