f(3)=1/4(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\int\frac{dy}{y}=\int (6-2x)dx[/tex]

[tex]-\frac{1}{y}=6x-x^2+C[/tex]

[tex]-4=18-9+C[/tex]

[tex]C=-13[/tex]

[tex]-\frac{1}{y}=6x-x^2-13[/tex]

[tex]y=-\frac{1}{6x-x^2-13}[/tex]

the answer is...

[tex]y=\frac{1}{6x-x^2+13}[/tex]

why?

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# Homework Help: F(3)=1/4 integration

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