# F preserves midpoint?

1. Jan 26, 2008

### pivoxa15

1. The problem statement, all variables and given/known data
Suppose f is an isometry that fixes O (origin). Prove f preserves midpoints of line segments.

3. The attempt at a solution
Geometricallly, f could be a reflection in which case it would not preserve the mid point of any line segment that does not intersect the origin anywhere.

So I don't see a proof at all and infact sees a mistake.

2. Jan 26, 2008

### psi^

But in the case of a reflection the transformation of a midpoint is still a midpoint, no?

3. Jan 26, 2008

### pivoxa15

That is true. I was thinking along the wrong lines (no pun intended) in that I was thinking that f maps midpoint to the exact same mid point.

Everything makes geometric sense. The only problem is to prove it algebraically. Can't see how to do it.

4. Jan 26, 2008

### Mathdope

Are we in R^n?

5. Jan 26, 2008

### psi^

If f is a isometry, u.v=f(u).f(v) holds. So the vector norm (u.u)^1/2 and distance stays the same.

Last edited: Jan 26, 2008
6. Jan 26, 2008

### pivoxa15

I have worked out the quesion in the OP. I now need to show that f(ru)=rf(u) with the same conditions given in the OP.