(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An element crystallises in a face-centered cubic lattice with a basis group of two atoms at [000] and [1/4 1/4 1/4]. The lattice constant is 3.55 x 10^-10 m

(Q1) How many nearest and second-nearest neighbours does each atom have?

(Q2) Calculate the average volume per atom

2. Relevant equations

3. The attempt at a solution

Ok, well I tried doing (Q2) I cant make sense of (Q1) though.

For (Q2) I used equation :

(4/3)(pi)(r²) = volume of atom

and r = {√3}/4 x lattice constant

But I dont think this is the case since I want the average volume per atom?

Thanks.

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# Face-centered cubic lattice.

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