(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An element crystallises in a face-centered cubic lattice with a basis group of two atoms at [000] and [1/4 1/4 1/4]. The lattice constant is 3.55 x 10^-10 m

(Q1) How many nearest and second-nearest neighbours does each atom have?

(Q2) Calculate the average volume per atom

2. Relevant equations

3. The attempt at a solution

Ok, well I tried doing (Q2) I cant make sense of (Q1) though.

For (Q2) I used equation :

(4/3)(pi)(r²) = volume of atom

and r = {√3}/4 x lattice constant

But I dont think this is the case since I want the average volume per atom?

Thanks.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Face-centered cubic lattice.

**Physics Forums | Science Articles, Homework Help, Discussion**