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So I've been asked to prove that:
lim (n-->infinity) [2^n]/sqrt(n!) = 0
I've tried fiddling with Stirling and L'Hospital, but can't find my way through it.
Any thoughts?
lim (n-->infinity) [2^n]/sqrt(n!) = 0
I've tried fiddling with Stirling and L'Hospital, but can't find my way through it.
Any thoughts?