- Thread starter Paul245
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(2i + 1)! = (2i+1)(2i!)[itex]\frac{2 i}{(2 i + 1)!}[/itex] = [itex]\frac{1}{(2 i)!}[/itex] - [itex]\frac{1}{(2 i + 1)!}[/itex]

Could anybody please show what it is that needs to be done on LHS to get to RHS in this identity.

Nah, you've gone at that the wrong way.[itex]\frac{2i}{(2i+1)!}[/itex]=[itex]\frac{2i}{(2i+1)(2i)! }[/itex]

=[itex]\frac{2i}{2i(2i)! + (2i)! }[/itex]

= [itex]\frac{2i}{2i(2i)! + 2i (2i - 1)! }[/itex]

= [itex]\frac{1}{(2i)! + (2i - 1)! }[/itex]

and now what?

Start with the question, and use coolul007's hint to get a common denominator on the right hand side.

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