- #1

- 13

- 0

Could anybody please show what it is that needs to be done on LHS to get to RHS in this identity.

- Thread starter Paul245
- Start date

- #1

- 13

- 0

Could anybody please show what it is that needs to be done on LHS to get to RHS in this identity.

- #2

coolul007

Gold Member

- 265

- 7

(2i + 1)! = (2i+1)(2i!)

Could anybody please show what it is that needs to be done on LHS to get to RHS in this identity.

- #3

- 13

- 0

=[itex]\frac{2i}{2i(2i)! + (2i)! }[/itex]

= [itex]\frac{2i}{2i(2i)! + 2i (2i - 1)! }[/itex]

= [itex]\frac{1}{(2i)! + (2i - 1)! }[/itex]

and now what?

- #4

- 45

- 0

Nah, you've gone at that the wrong way.

=[itex]\frac{2i}{2i(2i)! + (2i)! }[/itex]

= [itex]\frac{2i}{2i(2i)! + 2i (2i - 1)! }[/itex]

= [itex]\frac{1}{(2i)! + (2i - 1)! }[/itex]

and now what?

Start with the question, and use coolul007's hint to get a common denominator on the right hand side.

- #5

- 631

- 0

Another way to go about: Add and subtract 1 in the numerator and club 2i and 1.

- #6

- 13

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thanks acabus, all

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