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Factorial in example problem, I'm confused

  1. Dec 1, 2004 #1
    I'm confused from one step to the next in the book.

    In the first step, they have (n+1)!

    then in the next step the write that as (n+1)n!

    so (n+1)! = (n+1)n! ?

    I don't understand that, can someone explain it to me ? ( I am very unfamiliar with factorials, this is like some of the first times I have seen it in computations.
  2. jcsd
  3. Dec 1, 2004 #2
    Let's take a general case:
    So in the problem:
    Now you can see that the terms after [itex](n+1)[/itex] are just [itex]n![/itex], according to our general definition above, so:
  4. Dec 1, 2004 #3
    The easiest way to see it is a concrete example I think. Take n as 5... then (n+1)! is 6! , which is 6*5*4*3*2*1. (n+1)n! is the same thing because n+1 is 6, then n! is 5*4*3*2*1, giving you 6*5*4*3*2*1.

    edit: posted late I guess :rolleyes:
  5. Dec 1, 2004 #4
    n! = 1 *2 * 3 ... *n

    (n + 1)! = 1 * 2 * 3 ... *n *(n+1)

    Since 1*2*3...*n = n!, you can rewrite the statement so that

    (n+1)! = (n+1)n!
  6. Dec 1, 2004 #5
    Ohhh i get it now, thanks guys! all of your responses helped me visualize it, ty.
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