- #1
Dannbr
- 9
- 0
so,
6! = 6*5*4*3*2*1
(n+2)! = (n+2)(n+1)(n)!
(2n+2)! = (2n+2)(2n+1)(2n)!
(500n+3)! = (500n+3)(500n+2)(500n+1)(500n)!
Are all these statements correct?
6! = 6*5*4*3*2*1
(n+2)! = (n+2)(n+1)(n)!
(2n+2)! = (2n+2)(2n+1)(2n)!
(500n+3)! = (500n+3)(500n+2)(500n+1)(500n)!
Are all these statements correct?